A father is twice as old as his son. 20 years back, he was twelve times as old as his son. What are their present ages ?
A
24 years, 12 years
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B
44 years, 22 years
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C
48 years, 44 years
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D
None of these
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Solution
The correct option is B44 years, 22 years Let the age of son be x years and father be 2x years. 20 years back, their ages were x−20 and 2x−20 As per the given condition, we get
2x−20=12(x−20)
⇒2x−20=12x−240 ⇒2x−12x=20−240 ⇒−10x=−220 ⇒x=22010
⇒x=22
∴ son's age is 22 years and father's age is (2×22)=44 years.