A father was twelve times as old as his son twenty years back. Now he is twice as old as his son. what are their present ages ?
A
Father 44 and son 22
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B
Father 35 and son 23
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C
Father 38 and son 44
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D
Father 55 and son 22
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E
None of these
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Solution
The correct option is D Father 44 and son 22 Let present age of the son =x Present age of the father =2x Now, according to question, we have 2x−20=12×(x−20) 2x−20=12x−240 10x=220 x=22 Present age son =22 years Present age father =2×22=44 years.