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Standard XII

Mathematics

Division and Distributuion into Groups of Unequal Sizes.

A father with...

Question

A father with $8$ children takes $3$ at a time to the Zoological Gardens, as often as he can without taking the same $3$ children together more than once. The number of times he will go to the garden is

336

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112

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56

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Solution

The correct option is C $56$
Father $⟶ 8$ children

Takes $3$ at a time

No $3$ same children taken again

required number = $^{8} C_{3}$

$= \frac{8!}{5! \times 3!} = \frac{8 \times 7 \times 6}{3 \times 2} = 56$

he will visit $56$ times

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A father with 8 children takes 3 at a time to the Zoological Gardens, as often as he can without taking the same 3 children together more than once. The number of times he will go to the garden is

The correct option is C 56Father ⟶8 children Takes 3 at a time No 3 same children taken again required number = 8C3=8!5!×3!=8×7×63×2=56he will visit 56 times

A father with $8$ children takes $3$ at a time to the Zoological Gardens, as often as he can without taking the same $3$ children together more than once. The number of times he will go to the garden is

The correct option is C $56$
Father $⟶ 8$ children

Takes $3$ at a time

No $3$ same children taken again

required number = $^{8} C_{3}$

$= \frac{8!}{5! \times 3!} = \frac{8 \times 7 \times 6}{3 \times 2} = 56$

he will visit $56$ times