A feather is dropped on the moon from a height of 13.36 m. The acceleration due to gravity on the moon is 1.67ms2. Determine the time taken by the feather to fall on the surface of the moon?
4 s
Using second equation of motion,
s=ut+12at2
13.36=0+12×1.67×t2
t=√26.721.67 s
t = 4 s