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Question

A feather is dropped on the moon from a height of 167 m. The acceleration due to gravity on the moon is 1.67 ms2​. Determine the time taken by the feather to fall on the surface of the moon.


Your Answer
A
103 s
Your Answer
B
52 s
Your Answer
C
103 s
Correct Answer
D
102 s

Solution

The correct option is B 102 s
Given,
distance covered (height) =167 m,
acceleration a=1.67 ms2 and
initial velocity, u=0

Let the time taken be 't'.
Using the second equation of motion, 
s=ut+12at2
167=0+12×1.67×t2
t=2×1671.67 s 
t=2×100 s
t=102 s
 

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