Question

A fertilizer plant decides to begin with a small batch of ammonia. They decide to start with $100mL$ of $N_2$ and $100mL$ of $H_2$ gas in their reaction vessel. How much ammonia should they expect to make?

• A. $67mL$
• B. $100mL$
• C. $167mL$
• D. $267mL$

Answer 1

The correct option is A $67mL$

$N_2+3H_2\to 2N{H}_3$

$100mL100mL$

To find the limiting reagent;

$N_2=\frac{\text{Volume of}{N}_2}{\text{Coefficient of}{N}_2}=\frac{100}{1}=100$

$H_2=\frac{\text{Volume of}{H}_2}{\text{Coefficient of}{H}_2}=\frac{100}{3}=33.3mL$

So, $H_2$ is limiting reagent $[33.3<100]$

So, $3moles$ of $H_2$ produce $2moles$ of $N{H}_3.$

So, $100mL$ of $H_2$ produce $67mL.$ of $N{H}_3.$