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Question

# A few electric field lines for a system of two charges Q1 and Q2 fixed at two different points on the xâˆ’axis are shown in the figure. These lines suggest that

A
|Q1|>|Q2|
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B
|Q1|<|Q2|
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C
at a finite distance to the left of Q1 the electric field is zero
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D
at a finite distance to the right of Q2 the electric field is zero
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Solution

## The correct options are A |Q1|>|Q2| B at a finite distance to the right of Q2 the electric field is zeroAs electric field lines are originating from Q1 and terminating at Q2⇒Q1 is +ve and Q2 is (-)ve.Density of field lines α strength of electric field α |Q|So, |Q1|>|Q2| (A)⇒E1= Electric field at P due to Q1 E2= Electric field at P due to Q2For Ep=0,E1−E2=0⇒E1−E2=0⇒E1=E2⇒kQ1(r+d)2=kQ2r2⇒Q1Q2=(r+d)2r2As |Q1|>|Q2|, so, such ′r′ exists.Hence, both option (A) and (D) are correct.

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