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Question

A few electric field lines for a system of two charges Q1 and Q2 fixed at two different points on the xaxis are shown in the figure. These lines suggest that
1011074_b4192a96a10e45c28aa1501c9dd17671.png

A
|Q1|>|Q2|
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B
|Q1|<|Q2|
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C
at a finite distance to the left of Q1 the electric field is zero
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D
at a finite distance to the right of Q2 the electric field is zero
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Solution

The correct options are
A |Q1|>|Q2|
B at a finite distance to the right of Q2 the electric field is zero
As electric field lines are originating from Q1 and terminating at Q2
Q1 is +ve and Q2 is (-)ve.
Density of field lines α strength of electric field α |Q|
So, |Q1|>|Q2| (A)

E1= Electric field at P due to Q1
E2= Electric field at P due to Q2
For Ep=0,E1E2=0
E1E2=0
E1=E2
kQ1(r+d)2=kQ2r2
Q1Q2=(r+d)2r2
As |Q1|>|Q2|, so, such r exists.
Hence, both option (A) and (D) are correct.


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