A field in shape of a quadrilateral has one diagonal of length 10 m, Perpendicular to the diagonal from the opposite corners are of lengths 7 m and 5 m.The area of the field is

m^{2}

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m^{2}

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120

m^{2}

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m^{2}

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Solution

The correct option is B 60 $m^{2}$
Area of field = $\frac{1}{2} \times 10 \times (7 + 5) m^{2}$
= 60 $m^{2}$

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A field in shape of a quadrilateral has one diagonal of length 10 m, Perpendicular to the diagonal from the opposite corners are of lengths 7 m and 5 m.The area of the field is

The correct option is B 60 m2Area of field = 12×10×(7+5)m2 = 60 m2

The correct option is B 60 $m^{2}$
Area of field = $\frac{1}{2} \times 10 \times (7 + 5) m^{2}$
= 60 $m^{2}$