A field is 150 m long and 100 m wide. A plot (outside the field) 50 m long and 30 m wide is dug to a depth of 8 m and the earth taken out from the plot is spread evenly in the field. By how much is the level of field raised?

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Solution

Length of the plot (l) = 50 m
Width (b) = 30 m
and depth (h) = 8 m
$∴$ Volume of the earth dug out = $l \times b \times h$
= $50 \times 30 \times 8 = 12000 m^{3}$
Length of the field = 150 m
and breadth = 100 m
$∴$ Height of the earth spread out on the field
= $\frac{V o l u m e}{l \times b} = \frac{12000}{150 \times 100} m = \frac{4}{5} m$
= 0.8m = 80 cm

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A field is 150 m long and 100 m wide. A plot (outside the field) 50 m long and 30 m wide is dug to a depth of 8 m and the earth taken out from the plot is spread evenly in the field. By how much is the level of field raised?

Length of the plot (l) = 50 m Width (b) = 30 m and depth (h) = 8 m ∴ Volume of the earth dug out = l×b×h = 50×30×8=12000m3 Length of the field = 150 m and breadth = 100 m ∴ Height of the earth spread out on the field = Volumel×b=12000150×100m=45m = 0.8m = 80 cm