wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A field is 1700cm long and 11 m broad. A rectangular pit of dimensions 6m×3.5m×2m is dug anywhere in this field and dug out soil is spread evenly over the remaining part of the field. The approximate rise in the level of the rest of the field is

A
11.23cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12.65cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9.57cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10.1cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 11.23cm
Length of the field=1700cm =17m

Breadth of the field=11m

Area of the field=17×11

=187m2

Volume of rectangular pit=6m×3.5m×2m

=42m3

Area of rectangular pit=6m×3.5m

=21m2

Remaining area=18721

=166m2

Rise in the field=volume of the soilremaining area

=42166

=.253m

=25.3cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Volume
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon