A field is $225 m$ long and $175 m$ wide. It has two roads in its centre of uniform width of $5 m$ , one parallel to its length and the other parallel to its breadth. Find the cost of levelling the roads at $R s . 3$ per square metre.

R s . 1975

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R s . 1125

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R s . 5925

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R s . 6125

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Solution

The correct option is C $R s . 5925$
Analyse the problem.

We see that the total road to be levelled= horizontal road+vertical road-the common portion to both.

Area of horizontal road= $225 m \times 5 m = 1125 m^{2}$
Area of vertical road= $175 m \times 5 m = 875 m^{2}$
Area of common portion: $5 m \times 5 m = 25 m^{2}$

Thus total area: $(1125 + 875 - 25) m^{2} = 1975 m^{2}$

Rate: $R s . 3 p e r m^{2}$

So, total cost= $1975 m^{2} \times R s .3 p e r m^{2} = R s . 5925$

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A field is 225 m long and 175 m wide. It has two roads in its centre of uniform width of 5 m, one parallel to its length and the other parallel to its breadth. Find the cost of levelling the roads at Rs.3 per square metre.

A field is $225 m$ long and $175 m$ wide. It has two roads in its centre of uniform width of $5 m$ , one parallel to its length and the other parallel to its breadth. Find the cost of levelling the roads at $R s . 3$ per square metre.