A field is in the shape of a trapezium whose parallel sides are $25$ m and $10$ m. The non-parallel sides are $14$ m and $13$ m. Find the area of the field.

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Solution

Parallel sides are $25 m$ and $10 m$

Non-parallel sides are $14 m$ and $13 m$

$\begin{matrix} A r e a = \frac{(a + b)}{(a - b)} \times \sqrt{(s - a) (s - b) (s - b - c) (s - b - d)} s = \frac{(a + b + c + d)}{2} = \frac{25 + 10 + 14 + 13}{2} = 31 a = l o n g p a r a l l e l s i d e = 25 b = s h o r t p a r a l l e l s i d e = 10 c = n o n p a r a l l e l s i d e = 14 d = n o n p a r a l l e l s i d e = 13 A r e a = \frac{(25 + 10)}{(25 - 10)} \times \sqrt{(31 - 25) (31 - 10) (31 - 10 - 14) (31 - 10 - 13)} = \frac{35}{15} \times \sqrt{6 \times 21 \times 7 \times 8} = \frac{35}{15} \times \sqrt{7056} = \frac{35}{15} \times 84 = 196 m^{2} \end{matrix}$

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A field is in the shape of a trapezium whose parallel sides are 25m and 10m.The non-parallel sides are14 m and 13 m. Find the area of the field.

Q. The area of a trapezium whose parallel sides are 25 m, 10 m and non-parallel sides are 14 m, 13 m is

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A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13m. Find the area of the field.

A field is in the shape of a trapezium whose parallel sides are $25$ m and $10$ m. The non-parallel sides are $14$ m and $13$ m. Find the area of the field.