A fighter plane, flying horizontally with a speed of 360 $k m / h$ at an altitude of 500 $m$ drops a bomb for a target straight ahead of it on the ground. At what approximate distance, the bomb should be dropped ahead of the target, so that it hits the target ? Assume that acceleration due to gravity, $g$ is $10 m s^{- 2}$ . Also neglect air drag.

1000

m

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50 \sqrt{5} m

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500 \sqrt{5} m

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866

m

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Solution

The correct option is A 1000 $m$
$x = u \sqrt{\frac{2 y}{g}} = 100 \sqrt{\frac{2 \times 500}{10}} = 1000 m$

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The correct option is A 1000 mx=u√2yg=100√2×50010=1000 m

The correct option is A 1000 $m$
$x = u \sqrt{\frac{2 y}{g}} = 100 \sqrt{\frac{2 \times 500}{10}} = 1000 m$