A fighter plane is moving in a verticle circle of radius 'r'. Its minimum velocity at the highest point A of the circle will be :

\sqrt{3 g r}

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\sqrt{2 g r}

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\sqrt{g r}

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\sqrt{g r / 2}

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Solution

The correct option is D $\sqrt{g r}$
Minimum velocity at the highest point of vertical circle $V A = \sqrt{g r}$

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A fighter plane is moving in a verticle circle of radius 'r'. Its minimum velocity at the highest point A of the circle will be :

The correct option is D √grMinimum velocity at the highest point of vertical circle VA=√gr

The correct option is D $\sqrt{g r}$
Minimum velocity at the highest point of vertical circle $V A = \sqrt{g r}$