A figure is formed by putting two squares one on the other as shown below. If the length of each side of the two squares is $8$ cm, then the perimeter of the formed figure is

56

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64

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32

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48

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Solution

The correct option is D $48$ cm
New dimensions are $b = 16$ & $l = 8$
$∴$ Perimeter of the figure formed
$= 16 + 8 + 16 + 8 = 48$ cm

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A figure is formed by putting two squares one on the other as shown below. If the length of each side of the two squares is 8 cm, then the perimeter of the formed figure is

The correct option is D 48 cmNew dimensions are b=16 & l=8∴Perimeter of the figure formed=16+8+16+8=48 cm

A figure is formed by putting two squares one on the other as shown below. If the length of each side of the two squares is $8$ cm, then the perimeter of the formed figure is

The correct option is D $48$ cm
New dimensions are $b = 16$ & $l = 8$
$∴$ Perimeter of the figure formed
$= 16 + 8 + 16 + 8 = 48$ cm