A fillet - welded joint is shown in the figure. The size of the weld is 8 mm safe stress in the weld is $120 N / m m^{2}$ . The safe force to which the weld can be subjected will be kN.

147.84

Open in App

Solution

The correct option is A 147.84

Throat thickness $= 0.7 \times$ Size of weld
$= 0.7 \times 8 = 5.6 mm$
$∴$ Safe force $= (80 + 60 + 80) \times 5.6 \times 120 \times 10^{- 3} k N$
$= 147.84 k N$
As thickness of plate is not given so no need to check for gross area yielding.

Suggest Corrections

Similar questions

Q. A 6 mm fillet weld is provided as shown below. The safe load (in kN) that can be transmitted by the fillet welded joint is

[Take permissible stress for fillet weld = 108 MPa]

Q. A fillet welded joint is subjected to transverse loading

F

as shown in figure. Both legs of the fillets are of

10 m m

size and the weld length is

30 m m

. If the allowable shear stress of the weld is

94 M P a

, considering the minimum throat of the weld, the maximum allowable transverse load in

k N

Two plates of 8 mm thickness each are connected by a fillet weld of 6 mm thickness as shown in figure below.

The permissible stresses in the plate and the weld are 160 MPa and 120 MPa, respectively. Assuming the length of the weld as shown in the figure to be the effective length, the permissible tensile load P is kN.

Q. A circular shaft of diameter 120mm is welded to a rigid plate by a fillet weld of size 6mm. If a torque of 8 kN-m is applied to the shaft, then the maximum stress induced in the weld is

Q. A circular plate of

200 m m

diameter is welded to another plate by a

6 m m

fillet as shown in figure. The maximum twisting moment that weld can resist is ____kN-m. (Use Fe410 grade of steel and shop welded)

Join BYJU'S Learning Program

A fillet - welded joint is shown in the figure. The size of the weld is 8 mm safe stress in the weld is 120 N/mm2 . The safe force to which the weld can be subjected will be kN. 147.84

The correct option is A 147.84 Throat thickness =0.7× Size of weld =0.7×8=5.6 mm ∴ Safe force =(80+60+80)×5.6×120×10−3kN =147.84kN As thickness of plate is not given so no need to check for gross area yielding.

A fillet - welded joint is shown in the figure. The size of the weld is 8 mm safe stress in the weld is $120 N / m m^{2}$ . The safe force to which the weld can be subjected will be kN.

147.84

The correct option is A 147.84

Throat thickness $= 0.7 \times$ Size of weld
$= 0.7 \times 8 = 5.6 mm$
$∴$ Safe force $= (80 + 60 + 80) \times 5.6 \times 120 \times 10^{- 3} k N$
$= 147.84 k N$
As thickness of plate is not given so no need to check for gross area yielding.