Question

A fillet welded joint is subjected to transverse loading $F$ as shown in figure. Both legs of the fillets are of $10mm$ size and the weld length is $30mm$. If the allowable shear stress of the weld is $94MPa$, considering the minimum throat of the weld, the maximum allowable transverse load in $kN$ is

• A. $17.92$
• B. $22.16$
• C. $19.93$
• D. $14.44$

Answer 1

The correct option is C $19.93$

The shear strength of the joint for single parallel fillet weld is
$P=\text{Throat area}\times \text{Allowable stress}$
$=t\times l\times \eta$
$t=\text{leg size}\times \sin {45}^{\circ }=0.707\times \text{leg size}$
For double parallel fillet weld
$P=2\times 0.707\times \text{leg size}\times l\times \eta$
$=0.707\times \text{leg size}\times (2\times 1)\times \eta$ [2l = 30]
$=0.707\times 0.01\times 0.03\times 94\times {10}^6=\mathrm{19.937.4}N$
$P=19.93kN$