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Question

A fillet welded joint is subjected to transverse loading F as shown in figure. Both legs of the fillets are of 10 mm size and the weld length is 30 mm. If the allowable shear stress of the weld is 94 MPa, considering the minimum throat of the weld, the maximum allowable transverse load in kN is

A
17.92
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B
22.16
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C
19.93
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D
14.44
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Solution

The correct option is C 19.93
The shear strength of the joint for single parallel fillet weld is
P=Throat area×Allowable stress
=t×l×η
t=leg size×sin45=0.707×leg size
For double parallel fillet weld
P=2×0.707×leg size×l×η
=0.707×leg size×(2×1)×η [2l = 30]
=0.707×0.01×0.03×94×106=19.937.4 N
P=19.93 kN

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