Question

A film show lasted for $3\frac{1}{3}$ hours. Out of his time, $1\frac{3}{4}$ hours was spent on advertisements. What was the actual duration of the film?

Answer 1

Actual duration of the film = Total duration of the show $-$ Time spent on advertisements
$$\begin{gathered} =\left(3\frac{1}{3}-1\frac{3}{4}\right)\mathrm{hours} \\ =\left(\frac{10}{3}-\frac{7}{4}\right)\mathrm{hours}\mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}3\mathrm{and}4=\left(2\times 2\times 3\right)=12 \\ =\left(\frac{40-21}{12}\right)\mathrm{hours}\left\{\left[12÷3=4,4\times 10=40\right]\mathrm{and}\left[12÷4=3,3\times 7=21\right]\right\} \\ =\left(\frac{19}{12}\right)\mathrm{hours}=1\frac{7}{12}\mathrm{hours} \end{gathered}$$
Thus, the actual duration of the film was $1\frac{7}{12}\mathrm{hours}$.