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Question

A filter transmits only radiation of wavelength greater than 440 nm. Radiation from a hydrogen discharge tube goes through such a filter and it’s incident on a metal of work function 1.8 eV. Find the stopping potential (in V) which can stop the photoelectrons. (Answer upto 2 decimal places)

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Solution


Energy of a photon
E=KEmax+ϕ0
KEmax=Eϕc
For a photon
λmin=1242 eV.nmΔE (eV)
=12422.55
=487 nm
KEmax=eVs
eVs=[2.551.8]eV
Vs=0.75 V

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