(a) Find k if the equations 4x2−11x+2k=0 and x2−3x−k=0 have a common root and obtain the common root for this value of k.
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Solution
(a) α217k=α6k=1−1 ∴(6k)2=17k(−1) or k(36k+17)=0 ∴k=0 and −17/36. Also from (1), α=17k6k=176 or α=6k−1=0 or 176. Hence the common root is either zero or 17/6.