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Question

$$(a)$$ Find the angle of incidence.
$$(b)$$ Find the angle between the incident and reflected rays.
Figure shows an incident ray $$AO$$ and the normal $$ON$$ on a plane mirror. The angle which the incident ray $$AO$$ makes with a mirror is $$30^{\circ}$$.

202301_8bcc43f134b64f32a7bf13ba9284d6e8.png


A
(a)60,(b)60
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B
(a)120,(b)120
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C
(a)60,(b)120
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D
(a)120,(b)60
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Solution

The correct option is B $$(a) 60^{\circ}, (b) 120^{\circ}$$
We know that angle of incidence and angle of reflection both are measured from normal which is perpendicular to the plane.
Let,
Angle of incidence $$=i$$
Angle of reflection $$=r$$
Normal ON is perpendicular to plane.
So, angle of incidence, $$i=90^0 - 30^0= 60^0$$
We know that angle of incidence$$=$$angle of reflection
So, angle of incidence$$=$$angle of reflection $$=$$$${60}^{0}$$
Hence, angle between incident ray(AO) and reflected ray(OB) is $$=i+r=60^0 + 60^0 = 120^0$$

242048_202301_ans_a988f2ed74e141b8bc0696aa59a4ca5c.png

Physics

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