Question 3a Find the value of the following-297 - 17-297 - 3

Name: NCERT - Grade 06 - Mathematics - Whole Numbers - Q11_1
Uploaded: 2022-07-04T10:36:42+05:30
Description: Using the distributive property (a×b) + (a×c) = a×(b+c) We get, 297× 17 +297× 3 = 297×(17+3 ) = 297× 20 = 5940 ...

Using the distributive property (a×b) + (a×c) = a×(b+c) We get, 297× 17 +297× 3 = 297×(17+3 ) = 297× 20 = 5940 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Distributivity

Question 3a F...

Question

Question 3(a)

Find the value of the following:

$297 \times 17 + 297 \times 3$

Open in App

Solution

Using the distributive property
(a×b) + (a×c) = a×(b+c)

We get,

$297 \times 17 + 297 \times 3$ = $297 \times (17 + 3)$

= $297 \times 20$

= $5940$

Suggest Corrections

Similar questions

Find the value of the following:

$297 \times 17 + 297 \times 3$

$297 \times 17 + 297 \times 3 =___$

Find the value of the following:

(a) 297 × 17 + 297 × 3 (b) 54279 × 92 + 8 × 54279

Q. Question 6(vi)
Using identities, evaluate:

297 \times 303

Join BYJU'S Learning Program

Explore more

Distributivity

Standard VI Mathematics

Join BYJU'S Learning Program

Question 3(a) Find the value of the following: 297×17+297×3

Using the distributive property (a×b) + (a×c) = a×(b+c) We get, 297×17+297×3 = 297×(17+3) = 297×20 = 5940

Question 3(a)

Find the value of the following:

$297 \times 17 + 297 \times 3$

Using the distributive property
(a×b) + (a×c) = a×(b+c)

We get,

$297 \times 17 + 297 \times 3$ = $297 \times (17 + 3)$

= $297 \times 20$

= $5940$