Question

# A fire hydrant (as shown in the figure) delivers water of density p at a volume rate L. The water travels vertically upward through the hydrant and then does 90 turn to emerge horizontally at speed V. The pipe and nozzle have uniform cross-section throughout. The force exerted by the water on the corner of the hydrant is

A
pVL
B
Zero
C
2pVL
D
2pVL

Solution

## The correct option is D $$\sqrt{2}pVL$$force exerted by the water=pVL in the horizontal directionand pVL in the vertical directionnow adding their magnitudes, we get,option(D).Physics

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