Question

A fire hydrant (as shown in the figure) delivers water of density p at a volume rate L. The water travels vertically upward through the hydrant and then does 90 turn to emerge horizontally at speed V. The pipe and nozzle have uniform cross-section throughout. The force exerted by the water on the corner of the hydrant is

• A. pVL
• B. Zero
• C. 2pVL
• D. $\sqrt{2}pVL$

Answer 1

The correct option is D $\sqrt{2}pVL$

force exerted by the water=pVL in the horizontal direction

and pVL in the vertical direction

now adding their magnitudes, we get,

option(D).