CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A fire hydrant (as shown in the figure) delivers water of density p at a volume rate L. The water travels vertically upward through the hydrant and then does 90 turn to emerge horizontally at speed V. The pipe and nozzle have uniform cross-section throughout. The force exerted by the water on the corner of the hydrant is
295626_3a17d97007514712965ace4e9386c30d.png


A
pVL
loader
B
Zero
loader
C
2pVL
loader
D
2pVL
loader

Solution

The correct option is D $$\sqrt{2}pVL$$
force exerted by the water=pVL in the horizontal direction
and pVL in the vertical direction
now adding their magnitudes, we get,
option(D).

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image