CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A firecracker exploding on the surface of a lake is heard as two sounds a time interval t apart by a man on a boat close to the water surface. Sound travels by a speed v in the air. The distance from the exploding firecracker to the boat is:

A
uvtu+v
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t(u+v)uv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t(uv)uv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
uvtuv
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D uvtuv
Sound reaches the man via two media (water and air).
Time taken by sound wave in air medium is tair=xvair=xv
x is the distance between the source and observer.
Time taken by sound wave in water medium is tw=xvw=xu
Here u>v. (Speed of sound in water is greater than speed of sound in air)
Hence tairtw=txvxu=tx(1v1u)=t.
Hence x=tuvuv

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed of Sound
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon