A fireman of mass 80 kg slides down a pole during a rescue mission. The force of friction is constant at 720 N. Find the acceleration of the man.

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Solution

Force of friction is upward
= 720 N

Force of gravity downward
= Mg = 8010
=800 N

So resultant force
= 800 -720 =80 N

F = ma
80 = 80 a
a=1 m/s^2

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A fireman of mass 80 kg slides down a pole during a rescue mission. The force of friction is constant at 720 N. Find the acceleration of the man.

Force of friction is upward = 720 N Force of gravity downward = M*g = 80*10 =800 N So resultant force = 800 -720 =80 N F = m*a 80 = 80* a a=1 m/s^2

Force of friction is upward
= 720 N

Force of gravity downward
= Mg = 8010
=800 N

So resultant force
= 800 -720 =80 N

F = ma
80 = 80 a
a=1 m/s^2