A fireman places a 20 m long ladder against the wall of a building to enter a window at a height of 12 m from the ground, what is the distance between the base of the ladder and the building?

12 m

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16 m

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18 m

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22 m

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Solution

The correct option is B 16 m
The figure given below illustrates the situation explained in the question.
Using Pythagoras Theorem,
we get,
$(A C)^{2} + (B C)^{2} = (A B)^{2}$

$\Rightarrow (B C)^{2} = (20)^{2} - (12)^{2} = 400 - 144$
$= 256$
$= (16)^{2}$

$∴$ Distance between the building and the ladder = BC = 16 m.

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Similar questions

Q. If the length of a ladder placed against a wall of a building is 20 meters and the height of a window at the point where the ladder touches the wall is 12 meters, what is the distance between the ladder and the building?

Q. A

15

m

long ladder reached a window

12

m

high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.

Question 3
A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.

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A fireman places a 20 m long ladder against the wall of a building to enter a window at a height of 12 m from the ground, what is the distance between the base of the ladder and the building?

The correct option is B 16 mThe figure given below illustrates the situation explained in the question. Using Pythagoras Theorem, we get, (AC)2+(BC)2=(AB)2 ⇒(BC)2=(20)2−(12)2 =400−144 =256 =(16)2 ∴ Distance between the building and the ladder = BC = 16 m.