Question

A fireman wants to slide down a rope. The breaking lead for the rope is $(3/4{)}^{th}$ of the weight of the man. With what minimum acceleration should the fireman slide down? (Acceleration due to gravity is $g$)

• A. $zero$
• B. $\frac{g}{4}$
• C. $\frac{3g}{4}$
• D. $\frac{g}{2}$

Answer 1

Answer: (B)

$\frac{g}{4}$

For minimum acceleration, $ma=mg-\frac{3}{4}mg$
or $a=g(1-\frac{3}{4})=\frac{g}{4}$