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First Order Reaction

A first-order...

Question

A first-order reaction has a half-life of $14.5 h r s$ . What percentage of the reactant will remain after $24 h r s$ ?

A

18.3

%

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B

31.8

%

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C

45.5

%

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D

68.2

%

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Solution

The correct option is C $31.8$ %
$k = \frac{2.303}{t} log (\frac{a}{a - x})$
$\frac{0.693}{14.5} = \frac{2.303}{24} log \frac{100}{(a - x)}$
On solving, $(a - x) = 31.8$ %

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