Question

A first-order reaction has a half-life period of 69.3 sec. At 0.10 $L^{-1}$ reactant concentration,the rate will be :

• A. ${10}^{-4}M{sec}^{-1}$
  
• B. ${10}^{-3}M{sec}^{-1}$
• C. ${10}^{-1}M{sec}^{-1}$
• D. $6.93\times {10}^{-1}M{sec}^{-1}$

Answer 1

The correct option is B ${10}^{-3}M{sec}^{-1}$

The correct option is (2)

The rate constant,$K=\frac{0.693}{t_{o}0.5}$

$\frac{0.693}{69.3}=0.01$

Rate=$K[A{]}^1$=$0.01\times 0.1$=${10}^{-3}mol/l/s$