Question

A first order reaction has a specific rate of ${10}^{-3}{sec}^{-1}$. How much time will it take from $10$ $g$ of the reactant to reduce to $7.5$ $g$? $(\log 2=0.3010;\log 4=0.6020and\log 6=0.7782)$

Answer 1

$t=\frac{2.303}{{10}^{-3}}log\left(\frac{10}{7.5}\right)$

$t=287.73sec$