A first order reaction has a specific reaction rate of $10^{- 2} s e c^{- 1}$ . How much time will it take for $20 g$ of the reactant to reduce to $5 g$ ?

693.0 s e c

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238.6 s e c

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138.6 s e c

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346.5 s e c

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Solution

The correct option is C $138.6 s e c$
$t = \frac{2.303}{k} l o g (\frac{a}{a - x})$

$t = \frac{2.303}{10^{- 2} / s} l o g (\frac{20 g}{5 g})$

$t = 138.6$ sec
Hence, the time required will be 138.6 sec.

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