MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Half life

A first order...

Question

A first order reaction is 50% completed in $1.26 \times 10^{14}$ s. How much time would it take for 100% completion?

A

$1.26 \times 10^{15} s$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

$2.52 \times 10^{14} s$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

$2.52 \times 10^{28} s$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

Infinite

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
Infinite

Conceptual

Suggest Corrections

thumbs-up

0

Similar questions

A first order reaction is 50% completed in $1.26 \times 10^{14} s .$ How much time would it take for 100% completion ?

$(a) 1.26 \times 10^{15} s (b) 2.52 \times 10^{14} s (c) 2.52 \times 10^{28} s (d) I n f i n i t e$

Q. A first order reaction is

50

1.26 \times 10^{14} s

. How much time would it take for

100

Q. A first-order reaction is

50

1.26 \times 10^{14} s e c

. How much time would it take for

100

Q. A first order reaction is 50% completed in 1.26 × 10^14 s. How much time would it take for 100% completion?

Q. The time taken for 10% completion of a first order reaction is

20 min

. How much time does it take for 19% completion?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Half Life

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon