A fish is 10.0cm from the front surface of a spherical fish bowl of radius 20.0cm, as shown in the figure. The walls of the bowl are thin,and their effects can be neglected. As observed from the point P (see figure), the fish is at a distance of:
A
6.7cm from the surface and appears magnified in size
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B
8.6cm from the surface and appears magnified in size
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C
10.3cm from the surface and appears diminished in size
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D
11.4cm from the surface and appears diminished in size
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Solution
The correct option is B8.6cm from the surface and appears magnified in size μ1=μwater=43μ2=μair=1μ2v−μ1u=μ2−μ1R1v−4/3−10=1−4/3−201v=160−430∴v=60×3030−240=60×30−210=−8.6cm