Question

A fish is swimming in a pool whose bottom surface is silver polished. If the depth of the pool is$H$ and the fish is at depth $h$ below the water surface, find where an observer in air will observe the image of the fish.

• A. $(H-h)/\mu$
• B. $2(H-h)/\mu$
• C. $(H+h)/\mu$
• D. $(2H-h)/\mu$

Answer 1

The correct option is D $(2H-h)/\mu$

$\begin{array}{c}\frac{\text{(AD) Apperent deapth}}{\left(RD\right)\text{real deapth.}}\\ \begin{array}{cc}& =\frac{{\mu }_{\text{air}}}{{\mu }_{\text{water}}}\\ AD& =\frac{1}{\mu }(2H-h)\end{array}\end{array}$

So option (D) is correct