A fish is swimming in a river at a depth of $20 c m$ from the surface of the water. The refractive index of water is $4 / 3$ . An eagle flying above the water will see the fish at a depth of ___ $c m$

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Solution

In the given situation,

Refractive index of water, $μ_{w a t e r}$ = $\frac{4}{3}$

Refractive index of water = $\frac{R e a l d e p t h}{A p p a r e n t d e p t h}$

Therefore, apparent depth = $\frac{20 \times 3}{4}$ = $15 c m$

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A fish is swimming in a river at a depth of 20 cm from the surface of the water. The refractive index of water is 4/3. An eagle flying above the water will see the fish at a depth of ___cm

In the given situation, Refractive index of water, μwater = 43 Refractive index of water = Real depthApparent depth Therefore, apparent depth = 20×34 = 15 cm

A fish is swimming in a river at a depth of $20 c m$ from the surface of the water. The refractive index of water is $4 / 3$ . An eagle flying above the water will see the fish at a depth of ___ $c m$

In the given situation,

Refractive index of water, $μ_{w a t e r}$ = $\frac{4}{3}$

Refractive index of water = $\frac{R e a l d e p t h}{A p p a r e n t d e p t h}$

Therefore, apparent depth = $\frac{20 \times 3}{4}$ = $15 c m$