A fish lies at the bottom of 4 m deep water lake. A bird flies 6 m above the water surface. Then distance between (Fish and Bird on same vertical line) -
μw=43
Real depth of fish D=4m
μw=Dd
⇒43=4d
Hence apparent depth of fish d=3m
It is given that the bird is 6m above the water surface.
Hence the distance between the bird and the image of the fish =6+3=9m
Hence the correct answer is option (A).