A fish lies at the bottom of a 4m deep water lake. A bird flies 6m above the water surface and refractive index of water is 43. Then the distance between
A
Bird and image of fish is 8m
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B
Fish and image of bird is 12m
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C
Fish and image of bird is 8m
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D
Fish and image of bird is 10m
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Solution
The correct option is B Fish and image of bird is 12m
Apparent depthReal depth=h′h=μaμw i.e h′4=14/3=34⇒h′=3m Therefore, distance between the bird and image of the fish =6+3=9m
If y′ is the apparent height of the bird above water, y′6=μwμa=43 ⇒y′=8m So distance between the fish and the image of bird =4+8=12m Option (b) is correct.