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Question

A fisherman hooks an old log of wood of weight 12N and volume 1000 cm3.  He pulls the log half way out of water.  The tension in the string at this instant is


  1. 8 N

  2. 10 N

  3. 7 N

  4. 12 N


Solution

The correct option is C

7 N


Forces acting on log will be, 

mg downwards

and buoyant force, 

(Vim)ρliquid g=(V2)ρwater g upwards.

Tension in string is,

T=Mg(V2)ρwater g=7N

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