Question

A Five-digit number divisible by $3$ are formed using $0,1,2,3,4,5$ without repetition. The total number of ways this can be done is

• A. $216$
• B. $240$
• C. $600$
• D. $3125$

Answer 1

Answer: (A)

$216$

Five digit number divisible by $3$

The rule for divisibility by $3$, $3$ the addition of the no should be a multiple of $3$

So, we can have

$1,2,3,4,5\to$ sum is $15$

and $0,1,2,4,5\to$ sum is $12$

We can have only these may no.