Total 5 digit numbers that can be formed without repetition=5!=120
For a number to be divisible by 4,the last 2 digits of that number must be divisible by 4.
Hence the unit digit can only be 2 or 4.
When the unit digit is 4,the tens digit can only be 2 ⇒ rest of the three digits can be arranged in 3!=6 ways.
when the unit digit is 2,then the tens digit can be 1 ⇒ rest of the three digits can be arranged in 3!=6 ways.
when the unit digit is 2,then the tens digit can be 3 ⇒ rest of the three digits can be arranged in 3!=6 ways.
when the unit digit is 2,then the tens digit can be 5 ⇒ rest of the three digits can be arranged in 3!=6 ways.
Hence, total possibilities=6+6+6+6=24.
Probability=24120=15=525⇒k=5