A flag pole 18 m high casts a shadow 9.6 cm long. The distance of the top of the pole from the far end of the shadow is _________.

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Solution

Disclaimer: The question has been modified to match the answer given in the book. The modified question is as follows.

A flag pole 18 m high casts a shadow 9.6 m long. The distance of the top of the pole from the far end of the shadow is _______.

Solution:

Let AB be the flag pole and BC be the length of its shadow.

AB = 18 m and BC = 9.6 m

AC is distance of the top of the pole from the far end of the shadow.

In right ∆ABC,

AC² = AB² + BC² (Pythagoras theorem)

⇒ AC² = (18)² + (9.6)²

⇒ AC² = 324 + 92.16 = 416.16

⇒ AC = $\sqrt{416.16}$ = 20.4 m

Thus, the distance of the top of the pole from the far end of the shadow is 20.4 m.

A flag pole 18 m high casts a shadow 9.6 m long. The distance of the top of the pole from the far end of the shadow is _20.4 m___.

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