A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.
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Solution
Let BC = 18m be the flag pole and its shadow be AB = 9.6 m. the distance of the top of the pole, C from the far end i.e. A of the shadow is AC.
In right angled ΔABC, AC2=AB2+BC2 [by Pythagoras theorem] ⇒AC2=(9.6)2+(18)2 AC2=92.16+324 ⇒AC2=461.16 ∴AC=√416.16=20.4m Hence, the required distance is 20.4m.