A flagstaff $17.5 m$ high casts a shadow of $40.25 m$ . The height of the building which casts a shadow $28.75 m$ long under similar conditions, will be

10 m

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12.5 m

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17.5 m

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21.25 m

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Solution

The correct option is A $12.5 m$
In $△ P S T$
$tan A = \frac{17.5}{40.25} = 0.43$

Similarly, in $△ P Q R$
$tan A = \frac{h}{28.75} \Rightarrow 0.43 = \frac{h}{28.75} \Rightarrow h = 28.75 \times 0.43 \approx 12.5$

Therefore, Answer is $12.5$

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A flagstaff 17.5 m high casts a shadow of 40.25 m. The height of the building which casts a shadow 28.75 m long under similar conditions, will be

The correct option is A 12.5 mIn △PSTtanA=17.540.25=0.43Similarly, in △PQRtanA=h28.75⇒0.43=h28.75⇒h=28.75×0.43≈12.5Therefore, Answer is 12.5

A flagstaff $17.5 m$ high casts a shadow of $40.25 m$ . The height of the building which casts a shadow $28.75 m$ long under similar conditions, will be

The correct option is A $12.5 m$
In $△ P S T$
$tan A = \frac{17.5}{40.25} = 0.43$

Similarly, in $△ P Q R$
$tan A = \frac{h}{28.75} \Rightarrow 0.43 = \frac{h}{28.75} \Rightarrow h = 28.75 \times 0.43 \approx 12.5$

Therefore, Answer is $12.5$