A flagstaff 5 m high stands on a building 25 m high. As observed from a point at a height of 30 m, the flagstaff and the building subtend equal angles. The distance of the observer from the top of the flagstaff is
A
5√32
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B
5√32
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C
5√23
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D
None of thses
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Solution
The correct option is B5√32 OB is the bisector of DOAC of DAOC ∴OCOA=BCAB=x√x2+302=525 ⇒x=30√24=302√6 ∴x=5√32