A flash light lamp is marked 3.5V and 0.28A. The filament temperature is 4250C. The filament resistance at 00C is 4Ω. then, the temperature coefficient resistance of the material of the filament is
A
8.5×10−3/K
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B
3.5×10−3/K
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C
0.5×10−3/K
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D
5×10−3/K
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Solution
The correct option is D5×10−3/K α=R2−R1R1t2−R2t1=12.5−44(425)−12.5(0)=5×10−3/k