A flask has a capacity of one litre. The amount of volume (in ml) of air that will escape from the flask if it is heated from $27^{o}$ $C$ to $37^{o}$ $C$ is (assume pressure constant (only integer part).

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Solution

At T=300K, V=1litre
Let on heating the gas ,new volume of gas becomes V at T=310k
Therefore at constant pressure
$\frac{V_1}{T_1}$ = $\frac{V_2}{T_2}$
$\frac{1}{300} =$ \frac { V }{ 310 }
V=1.0333litre
Since capacity of flask is one litre , therefore gas escaped out from the flask is 1-0.333litre=0.0333litre-33.3mL

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A flask has a capacity of one litre. The amount of volume (in ml) of air that will escape from the flask if it is heated from 27o C to 37o C is (assume pressure constant (only integer part).

At T=300K, V=1litreLet on heating the gas ,new volume of gas becomes V at T=310kTherefore at constant pressureV_1T_1=V_2T_21300=\frac { V }{ 310 }V=1.0333litreSince capacity of flask is one litre , therefore gas escaped out from the flask is 1-0.333litre=0.0333litre-33.3mL

A flask has a capacity of one litre. The amount of volume (in ml) of air that will escape from the flask if it is heated from $27^{o}$ $C$ to $37^{o}$ $C$ is (assume pressure constant (only integer part).