A flask has a volume of $0.25 d m^{3}$ . What volume of air will be displaced from the flask if it is heated from $300 K$ to $360 K$ ?

0.25 d m^{3}

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0.5 d m^{3}

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0.05 d m^{3}

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Solution

The correct option is A $0.05 d m^{3}$
Volume $α$ Temperature.
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

$\frac{0.25}{300} = \frac{V_{2}}{360}$
$∴ V_{2} = 0.3 d m^{3} o r L$
Volume of air displaced from the flask
$=$ V_2 - V_1$
$= 0.3 - 0.25$
$= 0.05 d m^{3}$

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