A flask holds 30 litres of curd. From this flask 3 litres of curd were taken out and traded by water. This process was repeated further two times. How much curd is now contained in the flask?

21.5

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21.6

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21.8

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21.9

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Solution

The correct option is D 21.9
Suppose a flask holds x units of a liquid from which
y units are taken out and traded by water. After
n operations, quantity of pure liquid left in the flask will be

$(x {(1 - \frac{x}{y})}^{n}]$ units

Given x = 30 and y = 3
Substituting in the above formula

$(30 {(1 - \frac{30}{3})}^{3}] = 21.9 litres$

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A flask holds 30 litres of curd. From this flask 3 litres of curd were taken out and traded by water. This process was repeated further two times. How much curd is now contained in the flask?

The correct option is D 21.9Suppose a flask holds x units of a liquid from which y units are taken out and traded by water. After n operations, quantity of pure liquid left in the flask will be (x(1−xy)n]units Given x = 30 and y = 3 Substituting in the above formula (30(1−303)3]=21.9 litres