Question

A flask of capacity $2L$ is heated from ${35}^{\circ }C$ to ${45}^{\circ }C$. What volume of air will escape from the flask?

• A. $10mL$
• B. $20mL$
• C. $60mL$
• D. $50mL$

Answer 1

The correct option is C $60mL$

From Ideal gas law equation,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$V_1=2L,T_1=35+273=308K$

$V_2=?,T_2=45+273=318K$

$V_2=\frac{2}{308}\times 318=2.06L$

The capacity of flask $=2L$

Volume of air escaped $=2.06-2=0.06L$ or $60mL$.

Hence, option C is correct.